容易发现解总存在,只需要倒过来构造即可。原题右移数组,所以需要从后往前构造的时候左移数组。数组长度只有 $1000$,暴力即可。
// Date: Wed Nov 22 20:46:50 2023
#include <climits>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <utility>
#include <vector>
using namespace std;
const int INF = 0x3f3f3f3f, MOD = 1e9 + 7;
const double eps = 1e-8;
const int dir[8][2] = {
{0, 1}, {0, -1}, {1, 0}, {-1, 0}, {1, 1}, {1, -1}, {-1, 1}, {-1, -1},
};
typedef long long ll;
typedef unsigned long long ull;
typedef vector<int> VI;
typedef pair<int, int> PII;
const ull Pr = 131;
#define LN ListNode
#define LNP ListNode *
#define TN TreeNode
#define TNP TreeNode *
#define For(i, a, b) for (int i = int(a); i < int(b); ++i)
#define Rof(i, a, b) for (int i = int(b) - 1; i >= int(a); --i)
#define For1(i, a, b) for (int i = int(a); i <= int(b); ++i)
#define Rof1(i, a, b) for (int i = int(b); i >= int(a); --i)
#define ForE(i, j) for (int i = h[j]; i != -1; i = ne[i])
#define f1 first
#define f2 second
#define pb push_back
#define has(a, x) (a.find(x) != a.end())
#define nonempty(a) (!a.empty())
#define all(a) (a).begin(), (a).end()
#define SZ(a) int((a).size())
#ifdef _DEBUG
#define debug1(x) cout << #x " = " << x << endl;
#define debug2(x, y) cout << #x " = " << x << " " #y " = " << y << endl;
#define debug3(x, y, z) \
cout << #x " = " << x << " " #y " = " << y << " " #z " = " << z << endl;
#else
#define debug1
#define debug2
#define debug3
#endif
#ifdef _DEBUG
struct ListNode {
int val;
ListNode *next;
ListNode() : val(0), next(nullptr) {}
ListNode(int val) : val(val), next(nullptr) {}
ListNode(int val, ListNode *next) : val(val), next(next) {}
};
struct TreeNode {
int val;
TreeNode *left;
TreeNode *right;
TreeNode() : val(0), left(nullptr), right(nullptr) {}
TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
TreeNode(int x, TreeNode *left, TreeNode *right)
: val(x), left(left), right(right) {}
};
#endif
const int N = 2010;
int a[N], t, n, b[N];
void my_rot(int l, int r, int pre) {
int i = l, j = pre;
while (i < j) {
swap(a[i], a[j]);
++i, --j;
}
i = pre + 1, j = r;
while (i < j) {
swap(a[i], a[j]);
++i, --j;
}
i = l, j = r;
while (i < j) {
swap(a[i], a[j]);
++i, --j;
}
}
int main(void) {
#ifdef _DEBUG
freopen("1650d.in", "r", stdin);
#endif
std::ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> t;
while (t--) {
cin >> n;
For1(i, 1, n) { cin >> a[i]; }
memset(b, 0, sizeof b);
Rof1(i, 1, n) {
if (i == a[i])
continue;
int ans = -1;
For1(j, 1, i - 1) {
if (a[j] == i) {
ans = j;
break;
}
}
b[i] = ans;
my_rot(1, i, ans);
}
For1(i, 1, n) { cout << b[i] << ' '; }
cout << '\n';
}
return 0;
}